フィルターのクリア

I am trying to plot, at x=pi/4, the variation of the error percentage along h (h increments from 0.01 to 0.5), using the first order central difference method for function f(x)=sinx. Can't figure out what's wrong with the code. Any help please?

1 回表示 (過去 30 日間)
MF
MF 2016 年 1 月 5 日
編集済み: Roger Stafford 2016 年 1 月 5 日
z = cos(pi/4);%Exact value
n=0;
for h=0.01:0.01:0.5;
n=n+1;
t(n) =((sin(pi/4)+(h))-(sin(pi/4)-(h)))/(2*h);
Percent_Error(n)= abs (((t(n)-(z))./z)*100);
end
hold on
plot (t, Percent_Error);

回答 (1 件)

Roger Stafford
Roger Stafford 2016 年 1 月 5 日
編集済み: Roger Stafford 2016 年 1 月 5 日
What you want for t(n) is:
t(n) =(sin(pi/4+h)-sin(pi/4-h))/(2*h);
In other words the increment 'h' should be applied to the argument of the sine function, not outside it.

カテゴリ

Help Center および File ExchangeLine Plots についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by