# How can I do this : { [5] [6] [7] [8:23] [24:39] [40:55] } --- these number are just an example

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Laurensius Christian Danuwinata 2015 年 12 月 22 日
コメント済み: Guillaume 2015 年 12 月 22 日
Hello,
I have two arrays a = [1 2 3 4 5 5] and b = [6 7 5 8 9]. I need to write them in CAN bit packing block with these Format
c = { [5] [6] [7] [8:23] [24:39] [40:55] } ( Number are just an example).
c is the combination between a and b. I've tried with this code :
c = unique([a b]);
strc = num2str(c);
splitc = strsplit(strc);
joinc = strjoin(splitc, ':');
strjoin ={joinc};
and it was wrong . At least how can I add a delimiter such as '[' and ']' in one element in my array? e.g. a = [1 2 3]
a1 =[1]--( it has to be string). Thanks for the help! :)
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Laurensius Christian Danuwinata 2015 年 12 月 22 日
Yes, that's correct , e.g. {[1:9]} . Maybe you could take a look in this link http://de.mathworks.com/help/xpc/io_ref/canbitpacking.html?s_tid=srchtitle

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### 回答 (2 件)

Renato Agurto 2015 年 12 月 22 日
Do you want something like this?
['[' strc(1) ':' strc(4) ']']
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Laurensius Christian Danuwinata 2015 年 12 月 22 日
one thing, It should be automatic cause the values of a1 and c1 could varies ,e.g. a1 = [0 8 16]; c1 =[7 8 16]; then the result should be : {[0:7] [8] [16]}

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Guillaume 2015 年 12 月 22 日

First, learn to read the documentation. The documentation that you linked clearly says that: "The data type [...] must be a MATLAB® cell array vector. [...] The cell array elements must be of type double array". There are no strings involved in this.
Secondly, I'm not even sure you've understood what the can bit packing function does. The bit-pattern is not the same at all as the data you want to transmit. There are many bit patterns that could be valid for transmitting a = [1 2 3 4 5 5]. The following bit-pattern is a possiblity: c = {0, 1:2, 3:4, 5:7, 8:10, 11:13)}, that's the minimum pattern to transmit a but will not transmit b = [2 2 3 4 5 5] as there is not enough bits to transmit the first number. Equally valid pattern is: c = {0:9, 10:19, 20:30, 31:41, 42:52, 53:63}.
The bit-pattern is defined by:
• how many numbers you want to pack into a double
• the maximum value of each of these numbers
Given the maximum values you want to transmit
maxvalues = [2 2 6 4 10 8]; %for example.
You can calculate the smallest bit-pattern with:
bitsrequired = floor(log2(maxvalues)) + 1;
endbits = cumsum(bitsrequired) - 1;
assert(endbits(end) <= 63, 'more bits are required than can fit into a double');
bitpattern = arrayfun(@(s, e) (s:e), [0, endbits(1:end-1)+1], endbits, 'UniformOutput', false)
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Guillaume 2015 年 12 月 22 日
Following onto the comment you wrote to Renato's answer while I was typing mine, if given inputs
startbits = [0 8 16];
endbits = [7 8 16];
To generate the corresponding bit pattern, you'd simply do:
bitpattern = arrayfun(@(s, e) s:e, startbits, endbits, 'UniformOutput', false);

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