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Looping on one line

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Patrick 2015 年 12 月 7 日
編集済み: Stephen 2019 年 6 月 19 日
I searched the forums and couldn't find anything like this. So either I am doing it completely wrong or there is another method to accomplish it. Here is the code
if true
% code
SpearMeanRhoAll = vertcat(SpearMeanRhoP2,SpearMeanRhoP3,SpearMeanRhoP4,SpearMeanRhoP5,SpearMeanRhoP6,SpearMeanRhoP7,SpearMeanRhoP8,SpearMeanRhoP9,SpearMeanRhoP10,SpearMeanRhoP11,SpearMeanRhoP12,SpearMeanRhoP13,SpearMeanRhoP14,SpearMeanRhoP15,SpearMeanRhoP16,SpearMeanRhoP17,SpearMeanRhoP18,SpearMeanRhoP19,SpearMeanRhoP20,SpearMeanRhoP21);
As you can see the variable "SpearMeanRhoAll" is composed of SpearMeanRhoPx where x goes from 2 to 21. Does anyone know how to loop like this on one line?
Thanks for any help.
  1 件のコメント
Adam 2015 年 12 月 7 日
How to do what in a loop? Loops are not generally meant to be done in one line other than loop-replacement functions like arrayfun.
In general you should never put yourself in a situation where you have 21 variables with names like that in the first place. Your SpearMeanRhoAll representation would be far better to be used right from the start.


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