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How to find eigen vectors?

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Sandy
Sandy 2015 年 12 月 4 日
回答済み: Marc 2015 年 12 月 5 日
I am using:
A= [-5, 2; 2, -2];
[EigVec, EigVal] = eig(A)
If I use Wolfram, I obtain Eigen Vectors = [1,2;1, -0.5]. Similarly, how can I get MatLab to scale it to 1?
  1 件のコメント
John D'Errico
John D'Errico 2015 年 12 月 5 日
編集済み: John D'Errico 2015 年 12 月 5 日
I answered this identical question before. You cannot get MATLAB to magically scale them as you desire. However, you can DIVIDE EACH VECTOR BY THE FIRST ELEMENT OF THAT VECTOR. Just do the scaling yourself. Take care that the first element is not zero.

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回答 (1 件)

Marc
Marc 2015 年 12 月 5 日
I love questions like this... As I am always confused?
Maybe it is the way you are setting it up in Wolfram but if you have the symbolic toolbox in Matlab you can use this....
>> A= sym([-5 2; 2 -2])
A =
[ -5, 2] [ 2, -2]
>> [EigVec, EigVal] = eig(A)
EigVec =
[ -2, 1/2] [ 1, 1]
EigVal =
[ -6, 0] [ 0, -1]
So you get something close to what you wanted?
Try something like this in Maple....
A := Matrix([[-5, 2], [2, -2]])
Eigenvectors(A)
Vector(2, {(1) = -1, (2) = -6}), Matrix(2, 2, {(1, 1) = 1/2, (1, 2) = -2, (2, 1) = 1, (2, 2) = 1})
So Matlab's Symbolic toolbox and Maple are reversing the signs which I don't think is a big deal and of course they put things in different spots... Again not a big deal but it just makes you wonder? Or not.

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