Error using - Matrix dimensions must agree. Error in WDO_SG_Code_PL_test1m (line 322) a2=aa-a1; i got the error my code segment is below can any one help me why this error came?
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sorry i can not paste the whole code this is a segment of code _______________________________________________________________
u(hour)=hour;
Clothesdryer(hour)=power_pattern(hour,1);
a1=find(Clothesdryer);
Dish_washer(hour)=power_pattern(hour,2);
b1=find(Dish_washer);
Washing_Machine(hour)=power_pattern(hour,3);
c1=find(Washing_Machine);
oven(hour)=power_pattern(hour,4);
d1=find(oven);
iron(hour)=power_pattern(hour,5);
e1=find(iron);
Refrigerator(hour)=power_pattern(hour,6);
f1=find(Refrigerator);
Lightening(hour)=power_pattern(hour,7);
g1=find(Lightening);
Vaccume_cleaner(hour)=power_pattern(hour,8);
h1=find(Vaccume_cleaner);
PoolPump(hour)=power_pattern(hour,9);
i1=find(PoolPump);
EWH(hour)=power_pattern(hour,10);
j1=find(EWH);
Hairdryer(hour)=power_pattern(hour,11);
k1=find(Hairdryer);
AC(hour)=power_pattern(hour,12);
L1=find(AC);
%------------------------------------------% % xlswrite(filename1,WHeate)
end
Indexx
a2=aa-a1;
% a3=sum((a2)/9);
b2=bb-b1;
c2=cc-c1;
d2=dd-d1;
e2=ee-e1;
f2=ff-f1;
g2=gg-g1;
h2=hh-h1;
i2=ii-i1;
j2=jj-j1;
k2=kk-k1;
L2=LL-L1;
BAR(2,1)=sum_E_Cost_SS;
3 件のコメント
Torsten
2015 年 12 月 2 日
But how to subtract an 1x3 array from an 1x9 array ? Impossible.
Best wishes
Torsten.
回答 (1 件)
Thorsten
2015 年 12 月 2 日
Check the sizes by adding
whos aa
whos a1
before the a2=aa-a1; line.
aa and a1 must have the same size, otherwise you get the error.
4 件のコメント
Thorsten
2015 年 12 月 3 日
編集済み: Thorsten
2015 年 12 月 3 日
Zafar, you want to subtract 3 values from 9 values. That's not defined. One way to handle this would be
len = min([numel(aa) numel(a1]);
a2 = aa(1:len) - a1(1:len);
But I have no idea whether this makes sense in your code.
Maybe something needs to be fixed in the computation of aa and a1 such that they cannot have different sizes.
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