How do I store matrix solutions from a loop into another matrix?

How do I populate the T matrix with Tr matrices for each n=1:6, so that I can access the elements with T(3:3;3:3,2)?

T=zeros(6,1);

 for n= 1:6

    Tr = [c(n) -s(n)*ca(n)  s(n)*sa(n) a(n)*c(n);...
          s(n)  c(n)*ca(n) -c(n)*sa(n) a(n)*s(n);...
          0     sa(n)       ca(n)      d(n);... 
          0  0    0     1   ] ;

    T(:,:,n)=Tr;

Answer 1

[dpb]

T has to be size of Tr in each plane; not sure where you got the 6,1 from...

T=zeros(4,4,6);
for n=1:6
  T(:,:,n)=[c(n) -s(n)*ca(n)  s(n)*sa(n) a(n)*c(n);...
            s(n)  c(n)*ca(n) -c(n)*sa(n) a(n)*s(n);...
            0     sa(n)       ca(n)      d(n);     ... 
            0     0           0          1        ];

[Lorenzo]

great, it works. I was thinking as T as a 6x1 array with matrix elements in it, rather than a 3D matrix.

Thanks!

[dpb]

"T as a 6x1 array with matri[ces] in it..."

That would be a cell array, then...

T{n,1}=RHS;

instead. See

doc cell % and background info on cell arrays for details