Eliminate of empty matrix on cell structure.
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Hi everbody.
I have 1*1724 cell structure and i want to find which cells are not empty matrix.
for l=1:1:1724
if buyuk_elemanlar{1,l}==[];
clear buyuk_elemanlar{1,l}
elseif
???
end
end
I don'nt know how type matlab code after the "elseif"?

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回答 (2 件)
Image Analyst
2015 年 11 月 29 日
Try it like this:
if isempty(buyuk_elemanlar{1,l})
% Cell is empty....
Jan
2015 年 11 月 29 日
Use isempty instead of | == []|. clear is not useful to remove a single element. Do not remove elements of the cell inside the loop. Because then the loop index does not match the cell index anymore.
Different solutions:
m = false(1, 1724);
for k = 1:1724
if isempty(buyuk_elemanlar{1, k})
m(k) = true;
end
end
buyuk_elemanlar(m) = [];
Or:
m = false(1, 1724);
for k = 1:1724
m(k) = isempty(buyuk_elemanlar{1, k})
end
buyuk_elemanlar(m) = [];
Or:
m = cellfun('isempty', buyuk_elemanlar);
buyuk_elemanlar(m) = [];
The meaning of the "elseif ???" cannot be guessed. What should happen when the cell is not empty?
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