How to plot the magnitude and phase of a given transfer function(z-domain)?

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Daniel Ramirez
Daniel Ramirez 2015 年 11 月 27 日
I tried approacting this by doing the LTI function:
>> z=tf('z'); >> H=0.203*[(1-z^-1)*(1-0.2743*z^-1+z^-2)]/[(1+0.2695*z^-1)*(1+0.4109*z^-1+0.6758*z^-2)]
H =
0.203 z^8 - 0.2587 z^7 + 0.2587 z^6 - 0.203 z^5
-----------------------------------------------
z^8 + 0.6804 z^7 + 0.7865 z^6 + 0.1821 z^5
I don't even know if I'm approacting this right, please I need help in doing this.
  1 件のコメント
Daniel Ramirez
Daniel Ramirez 2015 年 11 月 28 日
編集済み: Daniel Ramirez 2015 年 11 月 28 日
I think I did it?
L=1000;
dw=2*pi/L;
w = -pi:dw:pi-dw;
aa=[1,0.6804,0.953486,0.182128];
bb=[0.2031,-0.2588,0.2588,-0.2031];
HH=freqz(bb,aa,w);
mag=abs(HH);title('Magnitude response')
figure
phase=angle(HH);title('Phase response')
plot(w,mag)
plot(w,phase)
The next step that they want me to do is plot the impulse response. So anyone know how to go from the freq domain to the time domain(n)? This is what I'm struggling the most, any help would be appreciated.

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回答 (2 件)

Aik-Siong Koh
Aik-Siong Koh 2021 年 7 月 8 日

ANNALURU R R SREENIVASA MURTHY
ANNALURU R R SREENIVASA MURTHY 2021 年 11 月 15 日
編集済み: ANNALURU R R SREENIVASA MURTHY 2021 年 11 月 15 日
You can use 'imp' function to plot impulse response.

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