Evaluate a function with "evalin"
古いコメントを表示
I am trying to run a function, and for doing so I need some values/ parameters that I have in the base workspace. Can someone tell me why this does not work? How can I fix it?
x0 = [0.5 ; 0.5 ] ;
evalin('base', 'fsolve(@price2T_ss, x0)') ;
[x, fval, exitflag] = evalin('base', 'fsolve(@price2T_ss,x0)') ;
Error message: ??? Undefined function or variable 'yT_y2'.
... where yT_y2 is a parameter that exists and is already defined in the base workspace, but not in the function's workspace.
Thanks a lot!!
Kyriacos
回答 (2 件)
Daniel Shub
2012 年 1 月 10 日
2 投票
This is one of the reasons not to use eval, it makes debugging difficult. I would guess that the price2T_ss function is trying to use yT_y2 and you haven't passed yT_y2 to it. You should also note that I am pretty sure the x0 you are defining in your function workspace is not being by fsolve. Why not just pass yT_y2 to your function so you do not have to do evalin.
5 件のコメント
Kyriacos
2012 年 1 月 10 日
Daniel Shub
2012 年 1 月 10 日
The eval, evalin, and assignin functions are powerful and probably will let you do whatever you want "automatically". That said, I cannot imagine a situation in which your code is relevant and that you would want to do it. You are already experiencing problems with it. Please, for your own sanity, pass the arguments that you need into your function and return only the arguments that you need and get rid of all uses of eval/evalin.
Robert Cumming
2012 年 1 月 10 日
+1. do not use eval for this (or pretty much anything...), its slow, error prone, will lead to problems/bugs etc...
Jan
2012 年 1 月 10 日
+1. Use EVAL only for these cases:
1. code obfuscation: a kind of tedious copy protection.
2. if you really need to define global variables dynamically: there is no function form like "global('a')"
Btw: avoiding globals is a good programming practize also...
Walter Roberson
2012 年 1 月 11 日
There are also some cases having to do with constructing function handles dynamically.
Walter Roberson
2012 年 1 月 10 日
0 投票
The fsolve() gets invoked within the base workspace, but the price2T_ss gets invoked from fsolve() or one of its subroutines, and so does not have direct access to the base workspace.
3 件のコメント
Kyriacos
2012 年 1 月 10 日
Walter Roberson
2012 年 1 月 10 日
Changing fsolve() would not be good enough: you would need to change price2T_ss .
You should consider using nested functions with shared variables rather than going through the base workspace.
Kyriacos
2012 年 1 月 11 日
カテゴリ
ヘルプ センター および File Exchange で Performance and Memory についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!