If statement in cell array; skip row if it equals certain value

8 ビュー (過去 30 日間)
JH
JH 2015 年 11 月 23 日
コメント済み: JH 2015 年 11 月 24 日
Hi all, I have a cell structure named RigidBodies, which contains five structures. These structures contain from 1 to 4 cells named Marker + number. Each Marker contains three columns with x,y and z data through time. I wrote a loop to subtract a specific value (eg. x0, y0 and z0) from the x, y and z values if the Marker cell is not empty and if the values of x,y and z are different than 0. If the values are 0, I want the rows to stay as they are. Below is my code, which does not report any error and neither does its job - it does not subtract the desired value (sample data is attached). What is wrong? Thank you.
Jurij Hladnik
Subtract = RigidBodies(1).Marker4(1,:);
for c = 1 : length(RigidBodies);
nmarkers = fieldnames(RigidBodies(c));
nmarkers = sum(strcmp(cellfun(@(x) x(1:end-1), nmarkers, 'un', 0), 'Marker'));
for d = 1 : nmarkers
~isempty(RigidBodies(c).(sprintf('Marker%d',d)))
for f = 1 : length (RigidBodies(c).(sprintf('Marker%d',d)))
if (RigidBodies(c).(sprintf('Marker%d',d))(f,:)==[0,0,0])
continue
else
RigidBodies(c).(sprintf('Marker%d',d))(f,:) = RigidBodies(c).(sprintf('Marker%d',d))(f,:) - Subtract;
end
end
end

回答 (1 件)

Thorsten
Thorsten 2015 年 11 月 23 日
編集済み: Thorsten 2015 年 11 月 24 日
Subtract = RigidBodies(1).Marker4(1,:);
for c = 1 : numel(RigidBodies)
nmarkers = fieldnames(RigidBodies(c));
for d = 1:numel(nmarkers)
x = getfield(RigidBodies, {c}, nmarkers{d});
if ~isempty(x)
idx0 = find(sum(x,2) == 0);
x = bsxfun(@minus, x, Subtract);
for e = idx0, x(e, :) = [0, 0, 0]; end
RigidBodies = setfield(RigidBodies, {c}, nmarkers{d}, x);
end
end
end
  3 件のコメント
Thorsten
Thorsten 2015 年 11 月 24 日
Dear JH,
there was an error in my code. I corrected it, it should work now.
JH
JH 2015 年 11 月 24 日
Still doesn't work. I get the following error: "Subscripted assignment dimension mismatch."

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeLoops and Conditional Statements についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by