Error Using "bvp4c" - "a singular Jacobian encountered"

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Abdulla Al-Mohannadi
Abdulla Al-Mohannadi 2015 年 11 月 8 日
コメント済み: MOSLI KARIM 2023 年 11 月 7 日
Hi,
I'm trying to run the following code, but keep running into an error:
function bvp5
xlow=0; xhigh=1;
solinit = bvpinit(linspace(xlow,xhigh,100),[1 -1]);
sol = bvp4c(@bvp5ode,@bvp5bc,solinit);
xint = linspace(xlow,xhigh);
Sxint = deval(sol,xint);
plot(xint,Sxint(1,:))
function dydx = bvp5ode(x,y)
dydx = [ y(2) (-1-y(2)/x)];
function res = bvp5bc(ya,yb)
res = [ ya(1)-1 yb(2) ];
And I get an error involving "a single Jacobian encountered". It seems to plot fine if I use:
function dydx = bvp5ode(x,y)
dydx = [ y(2) (-1-y(2))];
I attached the differential equation I'm trying to solve as a picture, where "T" is y and "r" is x in the code above.
Thanks
  1 件のコメント
MOSLI KARIM
MOSLI KARIM 2023 年 11 月 7 日
function bvp5
xlow=0.00001; xhigh=1;
solinit = bvpinit(linspace(xlow,xhigh,100),[1 -1]);
sol = bvp4c(@bvp5ode,@bvp5bc,solinit);
xint = linspace(xlow,xhigh);
Sxint = deval(sol,xint);
plot(xint,Sxint(1,:))
function dydx = bvp5ode(x,y)
dydx = [ y(2) (-1-y(2)/x)];
function res = bvp5bc(ya,yb)
res = [ ya(1)-1 yb(2) ];

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回答 (1 件)

Torsten
Torsten 2015 年 11 月 9 日
The general solution of your equation is
y(x)=c1*log(x)+c2-x^2/4
with c1, c2 to be determined from the boundary conditions.
Now you can easily see that for the boundary conditions you want to prescribe, your equation does not have a solution.
Best wishes
Torsten.

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