how i can calculate the surface(2D) of delaunay triangulation ??????????????????

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ali hadjer
ali hadjer 2015 年 11 月 8 日
回答済み: Gautam 2025 年 2 月 11 日 8:51
I want to calculate the area(the surface) of a zone(2D) using the delaunay triangulation or convex hull, how can i do ?plzzzzzzzz i need help net = [1:n;rand([1,n])*x;rand([1,n])*y]; net1 = net; xx=net(2,:); yy=net(3,:); dt = DelaunayTri(xx',yy'); P = [xx',yy']; K = convexHull(dt); triplot(dt,'cyan');

回答 (1 件)

Gautam
Gautam 2025 年 2 月 11 日 8:51
Delaunay triangulation divides the 2D area into triangles without any overlapping. Once you have the triangulation, you can calculate the area of each triangle and sum them up to get the total area using the "polyarea" function.
% Sample data points
points = [0, 0; 1, 0; 1, 1; 0, 1; 0.5, 0.5];
% Perform Delaunay triangulation
tri = delaunay(points(:, 1), points(:, 2));
% Plot the triangulation
figure;
triplot(tri, points(:, 1), points(:, 2));
hold on;
plot(points(:, 1), points(:, 2), 'r*');
title('Delaunay Triangulation');
xlabel('X');
ylabel('Y');
grid on;
% Calculate the area of each triangle
area = 0;
for i = 1:size(tri, 1)
x = points(tri(i, :), 1);
y = points(tri(i, :), 2);
area = area + polyarea(x, y);
end
% Display the total area
fprintf('Total Area using Delaunay Triangulation: %.2f\n', area);

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