Problem with plotyy for standard deviation on my plot
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Hi, I want to plot the +1.5 and -1.5 standard deviation of my time series, in the same figure but with two y axes; but my code does not work.
plotyy(date,x,,[1.5*std,-1.5*stdd])
why?
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回答 (2 件)
dpb
2015 年 11 月 7 日
Well you didn't tell what you got for an error but for starters
is missing the x value for the second plot with an empty argument position. That won't work for sure. Secondly you have std as one of the values; it is the name of the function. I presume from the second you intended it to also be stdd
plotyy(date,x,date,[1.5*stdd,-1.5*stdd])
The orientation of the concatenation implies they are column vectors?
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dpb
2015 年 11 月 7 日
It isn't my code, no, it's your problem...so what, precisely, do you want plotted?
Walter Roberson
2015 年 11 月 8 日
drange = [min(date), max(date)];
plotyy(date, x, drange, repmat([1.5*stdd,-1.5*stdd], 2, 1))
I do not see any good reason to use two y axes; I would use the same y axis but with different colors
drange = [min(date), max(date)];
plot(date, x, 'k', drange, repmat([1.5*stdd, -1.5*stdd], 2, 1), 'r')
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