row by row matrix building
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Quick question here I hope. Am modifying some code, can't see why this won't work:
j=1
while ischar (tline);
%define indexes, below as idx, etc etc
tline = fgetl(fid); %reads the next line in input file
dt = textscan(tline,'%s','delimiter',',');
tm = datenum(dt{1}(didx));
d1 = str2double(dt{1}(1idx));
d2 = str2double(dt{1}(2idx));
d3 = str2double(dt{1}(3idx));
mat(j,:) = [tm d1 d2 d3]; ;
j = j+1;
tline = fgetl(fid);
end;
The stumbling block is the mat(j,:) portion. Error message says 'Subscripted assignment dimension mismatch.' Tried different ways of creating mat[] prior to this loop and in different ways but no luck. Could do a whole different approach, but don't want to build a whole new routine.
1 件のコメント
Image Analyst
2015 年 11 月 7 日
1idx, 2idx, and 3idx are not valid variable names.
回答 (1 件)
Image Analyst
2015 年 11 月 7 日
What is the size of mat? Does it have 4 columns? What is the value of tline and j when the error is thrown? Maybe try preallocating mat before the while loop
mat = zeros(1, 4);
5 件のコメント
Colin Edgar
2015 年 11 月 7 日
Image Analyst
2015 年 11 月 7 日
Yes, as long as there are the same number of elements on the right hand side as there are columns in the matrix. Can you finish answering my questions, like what is tline?
Colin Edgar
2015 年 11 月 7 日
Image Analyst
2015 年 11 月 7 日
Well you can't assign 4 numbers to an entire row of 7 columns. If you just want the first 4 columns assigned, you can index it like this:
mat(j,1:4) = [tm d1 d2 d3];
The final 3 columns (columns 5, 6, and 7) will be untouched and remain as zero.
Colin Edgar
2015 年 11 月 9 日
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