calculation of time series.

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SONI SONI
SONI SONI 2015 年 11 月 6 日
コメント済み: SONI SONI 2015 年 11 月 9 日
I have monthly (420 months) time series data of temperature . I need to calculate a another time series based on following formula:
x = T(month,i) - T(month,i-1)
where, T(month,i) is temperature of current month
T(month,i-1) is temperature of previous month
how to create a time series of x ?

回答 (3 件)

Thorsten
Thorsten 2015 年 11 月 6 日
編集済み: Thorsten 2015 年 11 月 6 日
diffdata = diff(ts.Data)
difftime = ts.Time(1:end-1)+diff(ts.Time)/2;
tsdiff = timeseries(diffdata, difftime)

Image Analyst
Image Analyst 2015 年 11 月 6 日
If the second index is the month number, what does the first index represent? Have you tried
x = diff(T(month,:))?
  2 件のコメント
SONI SONI
SONI SONI 2015 年 11 月 6 日
both represents month. month,i is number of month. we can write x = T(i) - T(i-1)
suppose i is current month (January) and i-1 is previous month (December)
Image Analyst
Image Analyst 2015 年 11 月 6 日
But originally you said T was a 2-D array - it had two indexes: for a row and a column. Now you're saying T is a 1D array taking only one index. Totally inconsistent. Which is it?????

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SONI SONI
SONI SONI 2015 年 11 月 9 日
Temperature is 2-D array. I am trying to say I have a arrays T (time series of temperature January to December 1*12). now I want to substrate temperature values from current month to previous month. for example feb - jan, mar - feb....
But I have solved this problem
x(i) = T(i) - T(i-1)
  2 件のコメント
Image Analyst
Image Analyst 2015 年 11 月 9 日
Now you're back to a 1-D array, NOT a 2-D array despite what you say, because it has only 1 index.
And your code just does diff() which is the same as what I gave you except in a function instead of a for loop.
I give up.
SONI SONI
SONI SONI 2015 年 11 月 9 日
Thank you sir, for the interest to help me.

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