Logical indexing of cell array
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Hi all,
There is a probably a very simple solution to this but my mind has gone blank. I have a matrix which I am filtering on using logical indexing of another matrix e.g.
new_matrix=old_matrix(diff_matrix>50)
This works fine however I am trying to do the same thing, this time with a cell array e.g
new_cell_Array=old_cell_Array(diff_matrix>50)
but in this instance nothing happens - the old array and new array are the same size. Any ideas of how I use indexing to filter to the same entries in my cell array as my matrix?
I hope this makes sense
3 件のコメント
Star Strider
2015 年 11 月 3 日
It makes sense, but since cell arrays have different structures, we need ‘old_cell_Array’ and ‘diff_matrix’ in order to provide any substantive help.
Saving them to a .mat file (use the save function) and attaching them here (use the ‘paperclip’ icon and complete both the ‘Choose file’ and ‘Save file’ steps) would be the easiest way to share them.
jnaumann
2015 年 11 月 4 日
Adam
2015 年 11 月 4 日
When I run your code on those arrays I get a result array that is 5 elements shorter than the old_cell_array so it seems to work fine. The syntax is certainly fine since diff_matrix is a logical array.
回答 (1 件)
I tried it with your variables and it worked fine.
>> size(old_cell_array)
ans =
196.00 1.00
>> new_cell_array=old_cell_array(diff_matrix>50);
>> size(new_cell_array)
ans =
191.00 1.00
Maybe you confused old_cell_array and old_cell_Array, or something like that?
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