# How do I find the (x,y) coordinates of the peaks and valleys of a graph?

331 ビュー (過去 30 日間)
Dave Phillips 2015 年 11 月 1 日

I am new to Matlab and I am not sure how to find the coordinates of the peaks or valleys of my graph. After looking online, I tried using findpeaks() which did give me the y-values of the local maxima of my function ((e^(−at))*cos(2πft), where t is time and a and f are constants). However, I have not been able to find the corresponding x-values (and findpeaks() omits a local max at the y-intercept). I am also not at all sure how to find the coordinates for the valleys (minima or "troughs").

サインインしてコメントする。

### 採用された回答

Image Analyst 2015 年 11 月 1 日
The x values are the second return argument of findpeaks(). It's the index number. Your formula does not have an x by name so you have to go with the index number. If you have a second array for t, then to get the t values you'd do
[peakValues, indexes] = findpeaks(y);
tValues = t(indexes);
To get valleys, you invert the signal, so that now what used to be valleys are now peaks, and use findpeaks() again
invertedY = max(y) - y;
[peakValues, indexes] = findpeaks(invertedY);
tValues = t(indexes);
##### 5 件のコメント表示非表示 4 件の古いコメント
Markus Wahl 2018 年 11 月 24 日
An alternative could be to take the absolute value of your vector to find only the indexes of both peaks and values.. Would need to go back and evaluate the original function to get the y-values, though.

サインインしてコメントする。

### その他の回答 (1 件)

Sergio Yanez-Pagans 2021 年 3 月 28 日
You can use my MATLAB file exchange function, it's really easy to implement and use:
Hope you find this useful!

サインインしてコメントする。

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by