nlms output problem. if i give the inputs as a). desired AOA = 20 . b). 1st interfer = 40 .c). 2nd interfer = -20 ..output for b) and c) are not coming correctly. please help with my code
1 回表示 (過去 30 日間)
古いコメントを表示
d = .5;
N=6;
thetaS = input(' What is the desired users AOA (in degrees)? ');
thetaI = input(' What is the 1st interferers AOA(in degrees)? ');
thetaIs = input(' What is the 2nd interferers AOA(in degrees)? ');
T=1E-3;
t=(1:100)*T/100;
it=1:100;
S=cos(2*pi*t/T);
thetaS = thetaS*pi/180;
I = randn(1,100);
thetaI = thetaI*pi/180;
Is = randn(1,100);
thetaIs = thetaIs*pi/180;
vS = []; vI = []; vIs = [];
i=1:N;
vS=exp(1j*(i-1)*2*pi*d*sin(thetaS)).';
vI=exp(1j*(i-1)*2*pi*d*sin(thetaI)).';
vIs=exp(1j*(i-1)*2*pi*d*sin(thetaIs)).';
w = zeros(N,1); snr = 10;
X=(vS+vI+vIs);
Rx=X*X';
mu=1/(4*real(trace(Rx)))
wi=zeros(N,max(it));
for n = 1:length(S)
x = S(n)*vS + I(n)*vI + Is(n)*vIs;
y=w'*x;
e = conj(S(n)) - y; esave(n) = abs(e)^2;
w = w + mu/(0.001+x'*x) * x.* conj(e) ;
wi(:,n)=w;
yy(n)=y;
end
w = (w./w(1)); % normalize results to first weight
theta = -pi/2:.01:pi/2;
AF_3 = zeros(1,length(theta));
for i = 1:N
AF_3 = AF_3 + w(i)'.*exp(1j*(i-1)*2*pi*d*sin(theta));
end
figure
hold on
xlabel('AOA (deg)')
ylabel('|AF_n|')
plot(theta*180/pi,abs(AF_3)/max(abs(AF_3)),'b')
axis([-90 90 0 1.1])
set(gca,'xtick',[-90 -60 -30 0 30 60 90])
legend('NLMS')
grid on
0 件のコメント
回答 (0 件)
参考
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!