Just a small problem
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Hi! Can you help me please with this problem: How can I Write a function that produces random integers From 1000 to 9999, and including the numbers of different 4-digit (with no repetition)? In MatLab...
2 件のコメント
Andrew Newell
2011 年 12 月 30 日
For a start, see randint: http://www.mathworks.com/help/toolbox/comm/ref/randint.html.
Izmir
2011 年 12 月 30 日
採用された回答
その他の回答 (3 件)
Jan
2011 年 12 月 31 日
Finite and no large table:
a = 0:9;
i1 = ceil(rand * 9);
a(i1 + 1) = [];
p = randperm(9);
result = i1 * 1000 + a(p(1:3)) * [100; 10; 1]
2 件のコメント
Fangjun Jiang
2011 年 12 月 31 日
B+
Daniel Shub
2011 年 12 月 31 日
This is how I would have done it.
Jan
2011 年 12 月 30 日
It really looks like a homework and your teacher/professor will not recommend this forum to other students any longer after your homework has been solved here. Be sure to mention the assistence you got, otherwise it would be cheating.
I'd prefer a solution, which is guaranteed to stop in finite time. But I have only this idea:
a = 0:9;
while true
b = a(randperm(10, 4)); % Matlab 2011b required
if b(1) ~= 0
break;
end
end
result = b * [1000; 100; 10; 1]
For earlier Matlab versions:
b = a(randperm(10));
...
result = b(1:4) * [1000; 100; 10; 1]
Jan
2011 年 12 月 30 日
An algorithm in finite time, but not really efficient:
K = perms(0:9);
K(K(:,1) == 0, :) = [];
index = ceil(rand * size(K, 1));
result = K(index, 1:4) * [1000; 100; 10; 1]
It is more efficient to create a [Nx4] table only instead of the [Nx10] table of perms:
K = VChooseKO(0:9, 4);
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