Matrix printing with unique values

Hi, I want to print a (4x3) matrix with random values between 1 and 12. I have done but the problem is that first, I want to print all 12 values (no missing value between 1 and 12). The second problem is that no value in the matrix cells should be repeated.

[Martin Schätz]

Hi, can you post your script so I know what you are actualy doing?

[Muhammad Bilal Qureshi]

dataresource_files = zeros(4,3);
 for i=1:4
  dataresource_files(i,1) = unique(fix(12*rand+1)); 
        dataresource_files(i,1) = randi([1 12]); 
        dataresource_files(i,2) = randi([1 12]);
        dataresource_files(i,3) = randi([1 12]);
 end

         dataresource_files

Answer 1

[Martin Schätz]

If you post some code I can elaborate and work with it, but like this I can only sugest to create vector from 1 to 12, permute it and reshape it to 4x3 matrix.

So the code would be like this:

 dataresource_files = randperm(12);
 dataresource_files = reshape(dataresource_files,[4 3]);

[Muhammad Bilal Qureshi]

dataresource_files = zeros(4,3); 
for i=1:4 
dataresource_files(i,1) = unique(fix(12*rand+1)); dataresource_files(i,1) = randi([1 12]); 
dataresource_files(i,2) = randi([1 12]); 
dataresource_files(i,3) = randi([1 12]); 
end

[Martin Schätz]

Hi again, with command randperm(n) your able to create random permutation where n = length of result and also ending number of permutation. So your code can be simplified like this:

dataresource_files = randperm(12);
dataresource_files = reshape(dataresource_files,[4 3]);

Each time you will run this code you will get new random order of numbers from 1 to 12 in array of 4x3 size.

[Walter Roberson]

Right, and more compactly,

dataresource_files = reshape(randperm(12),[4 3]);