Hi guys,
I have a simple code here. What am I trying to achieve is to get the values of theta1 and theta2 (basically, this is an inverse kinematics). the code gives the output, the problem now is, it is just give me the first output.
Here is the coding
function[theta1_deg,theta2_deg]= inverse_two_links(x2,y2)
r2 = 0.1404;
l1 = 0.3132;
cos_theta2 = (x2^2+y2^2-l1^2-r2^2)/(2*l1*r2);
sin_theta2 = sqrt(1-cos_theta2*cos_theta2);
theta2 = atan2(sin_theta2,cos_theta2);
k1 = l1 + r2 * cos(theta2);
k2 = r2 * sin(theta2);
theta1 = atan2(y2,x2) - atan2(k2,k1);
theta2_deg = theta2 * 180 /pi;
theta1_deg = theta1 * 180 /pi;
when i execute the code for instance, x=-0.1404,y=0.3132, it just give me only 90 degree which is for theta1. Could you help me to figure out, what happened actually in my code?
Thanks in advance..

 採用された回答

Star Strider
Star Strider 2015 年 10 月 16 日

0 投票

By default, MATLAB only returns the first output of a function if only one output is requested. To get both, ask for both. Call your function as:
[theta1_deg,theta2_deg]= inverse_two_links(x2,y2);

2 件のコメント

siti khadijah binti
siti khadijah binti 2015 年 10 月 16 日
Oh mai!!.. thanks Star Strider.
Star Strider
Star Strider 2015 年 10 月 16 日
My pleasure!

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