fitting my periodic function
2 ビュー (過去 30 日間)
古いコメントを表示
Hi firends,
I have a set of input and output data, and I also have the function with three free variables. How can I fit this function without getting into local min and max. My function is
a ./ abs(1-exp(-b*300e-6 + 2j*(2*pi*c./(lam*1e-9))*300e-6)).^2
with a,b and c being free variables.
Another fitting function for this problem is in the form of
(a^2*(1-b^2)^2+(4*a^2*b^2*sin(2*pi*c*300e-6/lam*1e-9)^2))/((1-b^2)^2+4*b^2*(sin(2*pi*c*300e-6/lam*1e-9))^2)
again with a,b and c being free variables.
1 件のコメント
Walter Roberson
2015 年 10 月 15 日
Question: are the free variables constrained to be real, or could they be complex? Is the output constrained to be real? (That would be a major constraint due to the complex component of the expression.)
回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Interpolation についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!