# Nested function global variable

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Robbie Peck 2015 年 10 月 15 日

function T = fun(theta)
global m
m = theta^2;
end
function out = fun2(t)
out=( (1-m*t^2)*(1-t^2) );
end
I have the two functions above. When I call for fun, it does not seem to be working. I am new to Matlab so it would be greatly appreciated if someone could help my understanding. Thanks

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### 採用された回答

Thorsten 2015 年 10 月 15 日

Add global m to your fun2; I also used point-wise multiplication and exponentiation to make it work.
function T = fun(theta)
global m
m = theta^2;
end
function out = fun2(t)
global m
out=( (1-m*t.^2).*(1-t.^2) );
end
Alternatively, you could define fun2 as an anonymous function; note that here fun2 is already a function handle, so you have to pass with without the @ to quad:
function T = fun(theta)
global m
m = theta^2;
fun2 = @(t) (1-m*t.^2).*(1-t.^2)
end
##### 1 件のコメント表示非表示 なし
Robbie Peck 2015 年 10 月 15 日
Thank you- It's the point wise stuff I'm not used to. I'm used to R!

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### その他の回答 (1 件)

Julia 2015 年 10 月 15 日

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