Reshape Cell to Matrix

1 回表示 (過去 30 日間)
Brian
Brian 2011 年 12 月 27 日
So I'm having an issue adjusting this function to work with my actual dataset and it may be because I still don't understand the function quite right. (See answer to my original question here - http://www.mathworks.com/matlabcentral/answers/24527-reshape-cell-to-matrix)
My actual dataset format is as follows....
data = {'06/03/2011','00163T10'
'06/06/2011','00163T10'
'06/07/2011','00163T10'
'06/03/2011','ABCDEFGH'
'06/06/2011','ABCDEFGH'
'06/07/2011','ABCDEFGH'
'06/03/2011','ABCDWXYZ'
'06/06/2011','ABCDWXYZ'};
How would I go about using the arguments above with a dataset in this format. Ultimately, I am attempting to create a logical matrix of whether the ticker was in or out (1 or 0) for each given day using the accumarray function that Andrei began to help me with in the example posted above.

採用された回答

Andrei Bobrov
Andrei Bobrov 2011 年 12 月 28 日
try this cod (small corrected, typo)
d1 = datenum(data(:,1),'mm/dd/yyyy');
[a1,c1,c1] = unique(d1);
[a2,c2,c2] = unique(data(:,2));
out1 = accumarray([c1,c2],ones(numel(c1),1),[max(c1),max(c2)],@(x){x},{0});
out = [{NaN}, a2'; cellstr(datestr(a1,'mm/dd/yyyy')),out1];
  2 件のコメント
Andrei Bobrov
Andrei Bobrov 2011 年 12 月 28 日
small corrected
Brian
Brian 2012 年 4 月 30 日
Sorry for being so slow to respond to this. You answer worked brilliantly and I have been using it for a while now.
Thanks Andrei,
Brian

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeMultidimensional Arrays についてさらに検索

製品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by