How to expand a summation with different indexes
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How to expand a summation with different indexes like this?
Any help would be appreciated.
4 件のコメント
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Thorsten
2015 年 10 月 2 日
sum(diff(f(1:4)).*n(1:3).*arrayfun(@(x) sum(m(x:end)), 3:5))
7 件のコメント
Muthu Annamalai
2015 年 10 月 2 日
@Thorsten : nice solution exploiting fact that each sum is independent of the other index, i and j, we may use dot products to compute the inner loop, and repeat it again for index i. I wonder if there is also a way to do it with mesgrid() and matrix products.
Sean de Wolski
2015 年 10 月 2 日
編集済み: Sean de Wolski
2015 年 10 月 2 日
sum(diff(f(1:4)).*n(1:3).*sum(m(3:5)))
5 件のコメント
Thorsten
2015 年 10 月 2 日
編集済み: Thorsten
2015 年 10 月 2 日
Sean, yes, i is 1:3, so the starting index of j is 3:5, so the sum runs for j = 3:5 for i = 1, j = 4:5 for i = 2, and j = 5 for i = 3, i.e., assumes values sum(m(3:5)), sum(m(4:5)) and sum(m(5)) for i=1,2,3. You forgot to sum over the different m(j), as far as I can see.
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