Subscripted assignment dimension mismatch.

 for i=1:i
      var(1,i) = find(m1==indexes(1,i));
       end

error is var(1,i) = find(m1==indexes(1,i));

Answer 1

[James Tursa]

The result of the find is likely a vector, and it appears you are trying to stuff this vector into a scalar spot. Do you need all of the find results, or maybe just one of them? If you need all of them, can you use a cell array for var? What is var being used for downstream in your code?

[Dhipikaa Sri Dhamotharan]

i need all the values. in starting stage till now i didnt use it any where

[Dhipikaa Sri Dhamotharan]

can u plz explain me with syntax...kindly help me with syntax to change

[James Tursa]

Not knowing what how var is going to be used downstream, I am just going to make a guess as to what might work for you with a cell array. Note that I changed your upper loop index to n ... it didn't make sense for the loop indexing to be i=1:i

 n = whatever
 var = cell(1,n);
 for i=1:n
     var{i} = find(m1==indexes(1,i));
 end

Downstream in your code, when you need to get at the results of the find you would use (note the use of the curly braces): var{i}