When I entered two arrays,
u = [1 2 3 4];v = [5 6 7 8];
and did the division using,
u/v
I got,
ans = 0.4023.
How to interpret the answer and what's the definition of array division like 'u/v' rather than element-wise 'u./v'?
Thanks.

 採用された回答

C.J. Harris
C.J. Harris 2011 年 12 月 20 日

0 投票

Usually u/v is equal to u*inv(v) in matrix terms.
However, since v does not have an inverse Matlab will calculate the Moore-Penrose pseudoinverse of v instead. This can also be done directly:
u*pinv(v) = 0.4023

その他の回答 (2 件)

Malcolm Lidierth
Malcolm Lidierth 2011 年 12 月 20 日

8 投票

Were you expecting this?
>> u = [1 2 3 4];v = [5 6 7 8];
>> u./v
ans =
0.2000 0.3333 0.4286 0.5000
Note the "." in
"./"
Sean de Wolski
Sean de Wolski 2011 年 12 月 20 日

1 投票

doc mrdivide
is a good place to start.

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