How can I get values outside of -90,90 degrees range when using asin?

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Ophion Dragon
Ophion Dragon 2015 年 9 月 15 日
回答済み: Walter Roberson 2015 年 9 月 15 日
Trying to get an answer of 147 degrees but the program always returns 33 degrees (within the range).

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Walter Roberson
Walter Roberson 2015 年 9 月 15 日
If you know you are in that quadrant then use (180 - asind(x))
If you do not know which quadrant then you need to know the sign() of the opposite and the radius in order to calculate the quadrant.

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