Hi,
I have a question regarding implementing a for and if loop with cell arrays.
I have a matrix A{1x24 cell} Each cell contains ages of people, but each cell has a different length (i.e. A{1} is 2362x1, while A{2} is 2344x1, etc.).
Now I want to apply an if loop that for each value in A which is >=1, that specific value will be subtracted by 1.
Can anyone help me with this?

 採用された回答

Stephen23
Stephen23 2015 年 9 月 14 日
編集済み: Stephen23 2015 年 9 月 14 日

0 投票

Some fake data to try, and the loop:
A{3} = 2:5;
A{2} = -3:4;
A{1} = -2:2;
for k = 1:numel(A)
idx = A{k}>=1;
A{k}(idx) = A{k}(idx) - 1;
end

3 件のコメント

Bas
Bas 2015 年 9 月 14 日
編集済み: Bas 2015 年 9 月 14 日
Thanks! This works..
One more question:
Now I have this updated matrix A as described above. I have a matrix B containing matrices, while A contains cells.
Matrix B contains ages from 26 up to 56 in the first column. The second column defines their salary.
I want to create a matrix C which contains the corresponding salaries of all people that are specified in A.
So something like this:
if floor(value in A) == B(:,1)
C(value)= B(value,2);
end
Stephen23
Stephen23 2015 年 9 月 14 日
編集済み: Stephen23 2015 年 9 月 14 日
Please ask this in a new question, giving both input and output example data for us to try. Currently it is not clear what "B containing matrices" means, ditto "The second column defines their salary", etc. Is the salary "defined" as a value, a code, a category, a name, an index, or something else?
Without example data arrays we cannot try our code and we cannot test our code.
Bas
Bas 2015 年 9 月 14 日
Thanks Stephen, I opened a new question.

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その他の回答 (1 件)

Walter Roberson
Walter Roberson 2015 年 9 月 14 日

0 投票

Anew = cellfun(@(V) V - (V>=1), A);

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Bas
2015 年 9 月 14 日

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Bas
2015 年 9 月 14 日

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