How to define the value of "t" from function f(t)
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Hello,
I have a function
f(t)=exp(-0.01*t.^2).*cos(2.*t)
where 't' is a function handle (f=@t)
I need to define 't' when f(t)=0.4.
How do I do this?
Sergey
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Walter Roberson
2015 年 9 月 9 日
It sounds to me like you might be attempting to solve exp(-0.01*t.^2).*cos(2.*t) to find the t where the expression becomes 0.4 . If so then there are an infinite number of solutions. You can find one of them by using
syms f(t)
f(t) = exp(-0.01*t.^2).*cos(2.*t);
vpasolve(f(t)=0.4)
2 件のコメント
Steven Lord
2015 年 9 月 9 日
Or if you don't have Symbolic Math Toolbox, you could use FZERO from MATLAB. Rewrite your expression so it's in the form g(t) = 0:
f = @(t) exp(-0.01*t.^2).*cos(2.*t);
g = @(t) f(t)-0.4; % Transforming f(t) = 0.4 -> f(t)-0.4 = 0
Then call FZERO to find a zero of g(t). Change the initial guess to locate additional zeros.
fzero(g, 0)
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