Image processing using indexing

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Dana
Dana 2011 年 12 月 15 日
Hi. I am wondering if anyone can help me. I'm not sure wether this is possible but i will try to explain it as best I can.
I have two images with the same resolution.
Image A, a RGB image.
Image B, a Gray scale image the with only a small region of postive values the rest black (0 values).
I wish to map a jet colormap to Image B and substitute these potive pixels into image A (repleaceing the pixels from A)
I understand that a grayscale image with a colormap is of a different format to a RGB image which is (m*n*3). But is it possible.
I hope i have explained it clearly enough.
I would be gratefull for any help. Thank you
Regards Dana

採用された回答

David Young
David Young 2011 年 12 月 15 日
The details depend on what class your images are, but here's an example that you can probably modify as needed.
% test data - an rgb image and a greyscale image the same size, with lots
% of zeros in it
A = imread('saturn.png');
p = imread('pout.tif');
B = zeros(size(A,1), size(A,2), class(p));
B(1001:1000+size(p,1), 501:500+size(p,2)) = p;
% apply the jet map to the greyscale image
if strcmp(class(B), 'double')
% assume values in range 0-1
Brgb = ind2rgb(B, jet);
else
nvals = double(intmax(class(B))) + 1;
Brgb = ind2rgb(B, nvals*jet(nvals));
end
% copy non-zero parts of B into A
ind = repmat(B ~= 0, [1 1 3]); % index array
Amod = A;
Amod(ind) = Brgb(ind);
% look at the result
imshow(Amod);
  5 件のコメント
David Young
David Young 2011 年 12 月 15 日
... and I'd recommend looking at the demo that Image Analyst mentions below, though you might want to get my simpler code going first.
Dana
Dana 2011 年 12 月 16 日
Hey David, Thanks for your help I have spent all this morning playing around with your code but i have gotten it working.
My problem was that image p = imread('pout.tif'); is a smaller size than image A = imread('saturn.png');
I did not realise that the lines:
B = zeros(size(A,1), size(A,2), class(p));
B(1001:1000+size(p,1), 501:500+size(p,2)) = p;
were creating an image the same size as A and placing the photo in it.
So i cut down the code to
nvals = double(intmax(class(B))) + 1;
Brgb = ind2rgb(B, nvals*jet(nvals));
ind = repmat(B ~= 0, [1 1 3]); % index array
Amod = A;
Amod(ind) = Brgb(ind);
% look at the result
imshow(Amod);
As my images are already the same size and unit 8.
I also applied my own colormap which took some playing around but it worked.
So thanks again for your help, you really helped me out I cant believe the solution was so simple. You should have seen the code i had written myself to try and solve this.
Regards
Dana

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その他の回答 (1 件)

Image Analyst
Image Analyst 2011 年 12 月 15 日
Dana: See my full blown demo in another related posting:
  1 件のコメント
Dana
Dana 2011 年 12 月 16 日
Thanks for your help. You demo was very informative

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