how to plot discontinuous functions in matlab?

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rr mm
rr mm 2015 年 9 月 6 日
回答済み: Daniel Garside 2018 年 3 月 2 日
Hi everyone!
I want to plot a simple floor function without connections between points in separate steps. I do this in maple with discont=true property. I used scatter function but I want to have straight line instead of circles. how can I do the same in matlab?
thanks for your attention!

回答 (3 件)

the cyclist
the cyclist 2015 年 9 月 6 日
Here is an example that sounds like what you want:
figure
x = 1:10;
y = 3 + (x>5);
h = plot(x,y,'.');
set(h,'MarkerSize',24)
ylim([2 5])
  1 件のコメント
rr mm
rr mm 2015 年 9 月 6 日
Dear friend,
it does the same scatter function, the result must be like this image.
thanks

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Walter Roberson
Walter Roberson 2015 年 9 月 6 日
Every function sampled at a finite number of points is effectively discontinuous and there is no way to automatically tell from the finite list of sampled points whether two adjacent points "should" be joined or not.
You need to either add some intelligence about where the discontinuities are, or you need to process them symbolically by calling into MuPad's discont() function
syms x
feval(symengine, 'discont', floor(x), sym('x = 1..5'))
and then somehow process the discontinuity set in constructing your numeric plot.
If you were to work in a MuPAD notebook, you could use http://www.mathworks.com/help/symbolic/mupad_ref/plot-function2d.html as that has discontinuity processing turned on by default. I have never seen an answer for what happens if you try to feval() a MuPAD plot from the MATLAB level.

Daniel Garside
Daniel Garside 2018 年 3 月 2 日
If you just want the visuals something like this works:
for i=1:10
plot([i, i+1],[i,i])
end

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