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Syntax a while loop

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Philosophaie
Philosophaie 2015 年 8 月 28 日
回答済み: Walter Roberson 2015 年 8 月 28 日
I am not sure I have the syntax right on my while loop: And I am taking the absolute value with the abs command.
EA1 = pi / 4;
diff = 1;
while (abs(diff) > 0.000001)
diff = (EA1 - e * sin(EA1) - MA) / (1 + e * cos(EA1));
EA1 = EA1 + diff;
end

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回答 (1 件)

Walter Roberson
Walter Roberson 2015 年 8 月 28 日
That syntax is fine. You do not need the () around the condition but it does not hurt.

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