finding a mathematical function that passes from specified points

40 ビュー (過去 30 日間)
mohammad 2011 年 12 月 11 日
There are some points on X-Y coordinates:
(10,91)
(30,92)
(50,93.2)
(100,93.5)
(125,94)
(250,95.2)
(350,95.4)
(500,95.1)
(550,95)
(750,94.5)
(1000,93.8)
It has been needed to find mathematical function( Y=f(X) ) that passes from above points.And mathematical function must be algebra in this form: y=a+bx^2+cx^3+dx^4+...+nx^K (Not sinusoidal and etc) that a,b,...,n and K are unknown.
There is a command in MATLAB, which named polyfit() but I can't set parameters of that truly. Please help me in finding of this function

サインインしてコメントする。

採用された回答

Paulo Silva 2011 年 12 月 11 日
x=[10 30 50 100 125 250 350 500 550 750 1000];
y=[91 92 93.2 93.5 94 95.2 95.4 95.1 95 94.5 93.8];
plot(x,y,'o')
n=8; %try with different n values
p=polyfit(x,y,n);
f = polyval(p,x);
plot(x,y,'o',x,f,'-')
4 件のコメント表示非表示 3 件の古いコメント
Paulo Silva 2011 年 12 月 11 日
sorry it's wrong and I'm trying to solve it, meanwhile you should use the p variable so y=p(1)*x^8+p(2)*x^7...+p(n)*x^(n-1)

サインインしてコメントする。

その他の回答 (1 件)

Walter Roberson 2011 年 12 月 11 日
There is no solution to that in the form stated. In order to find a solution, you would need to define a measurement that you could apply to the polyfit() output for various K, to allow you to choose which output was appropriate for your situation.
You will not be able to get a polynomial that fits those points exactly: you are going to encounter round-off error in all the calculations.
When you use a K less than length(X)-1 then polyfit() will do fitting to find the coefficients with minimum total error at the points specified. It is plausible that you might find a K less than length(X)-1 for which the total error is "good enough" for your purposes. (Keep in mind that even with K=length(X)-1 there is going to be error.) But we do not know what your error tolerance is.
1 件のコメント表示非表示 なし
mohammad 2011 年 12 月 11 日
Thanks Walter, tolerance could be 0.01 around any above points. OK I'll try varies k value for it.

サインインしてコメントする。

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!