Hi sir, i like to use optical flow using Horn-Schunck method,if i use two images of size 64x64,how the output will be?
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(i.e)size of output
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Walter Roberson
2015 年 8 月 22 日
Horn-Schunck is an algorithm; the size of the output is going to depend upon the implementation.
If you use http://www.mathworks.com/help/vision/ref/opticalflowhs.estimateflow.html then what is returned is an "optical flow object". The size of "objects" is not specified. By examining some of the surrounding documentation I can see that optical flow objects have some fields to hold the options that you selected, and possibly some information describing the system. They also hold the u and v arrays that indicate direction and magnitude for each point of the input image; those are each going to be double() with the same number of rows and columns as the input image.
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