strings

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Dylan
Dylan 2011 年 12 月 7 日
clear
clc
word=lower(double(input('Enter a character \n')));
letter = char(input('Guess a character : ','s'));
stat = findstr(word,letter);
I'm trying to get the user to enter any number of character(not case sensitive). Then enter any random character and see if it matches any character of their first input.
  2 件のコメント
Chandra Kurniawan
Chandra Kurniawan 2011 年 12 月 7 日
What are you trying todo??
You said that 'trying to get the user to enter any number'.
But your code :
word=lower(double(input('Enter a character \n')));
Now, how can I use command 'lower' with numerical (double) input??
command lower works only for string, right??
Chris
Chris 2011 年 12 月 7 日
I thought lower was to not make it not case sensitive. And I'm trying to get the user to any character, not just numbers.

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採用された回答

Chandra Kurniawan
Chandra Kurniawan 2011 年 12 月 7 日
Did you mean??
clear; clc;
word = lower(input('Enter a word : ','s'));
letter = input('Guess a character : ','s');
stat = findstr(word,letter);
if ~isempty(stat)
for x = 1 : length(stat)
fprintf('Character %c macthes with word %s in column %d\n',letter,word,stat(x));
end
else
fprintf('Character %c no found in word %s\n',letter,word);
end
  1 件のコメント
Dylan
Dylan 2011 年 12 月 7 日
Yep, exactly what I meant, thank you!

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その他の回答 (1 件)

Sven Schoeberichts
Sven Schoeberichts 2011 年 12 月 7 日
word = input('Enter a word: ', 's');
letter = input('Guess a character : ','s');
stat = ismember(letter,lower(word));
stat = 1: character is present in word
stat = 0: character is not present in word
  1 件のコメント
Dylan
Dylan 2011 年 12 月 7 日
Okay, I may should have been more specific. Suppose the word I input is loop. And I guess the letter o. I expect a return of 0 1 1 0. 1 representing the number of times o is in the word.

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