Volume of irregular shape
12 ビュー (過去 30 日間)
古いコメントを表示
I have for example X,Y,Z coordinates of 8 points which form an irregular shape. How can I calculate the volume with in this shape? Eg. coordinates area:
0 0 384,67
0 26,6 385,25
-47,85 26,6 385,9
-47,85 0 385,3
0 0 387,32
0 26,6 387,32
-47,85 26,6 387,32
-47,85 0 387,32
0 件のコメント
採用された回答
Torsten
2015 年 8 月 6 日
編集済み: Torsten
2015 年 8 月 6 日
4 件のコメント
Gregory Vernon
2015 年 8 月 6 日
編集済み: Walter Roberson
2025 年 1 月 22 日
This answer assumes that your volume is convex. If your volume is concave, this method will return a larger volume. If you know the connectivity, and your volume is orientable, you can use the method outlined here:
https://en.wikipedia.org/wiki/Polyhedron#Volume (see "Orientable Polyhedra") https://en.wikipedia.org/wiki/Orientability
その他の回答 (2 件)
Gara
2025 年 1 月 22 日
This is a very common question. If you are not very well used to MATLAB, just try simple method. Your object or shape seems convex. So use the below method.
Enter all (8) coordinates in a matrix array
Ex: A=[x,y,z;x1,y1,z1;............];
[k,av]=convhull(A)
You will get answer as av=?
This should give you the volume of your 3-D object.
0 件のコメント
参考
カテゴリ
Help Center および File Exchange で Bounding Regions についてさらに検索
製品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!