2 Column Matrix to 1 column Matrix
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Hello,
I have this Matrix
2 4
4 11
5 7
5 10
7 12
8 10
11 12
2 8
I want the output to be something like this
2 4 11 12 7 5 10 8 2
So basically start with the first element 2 and build the connection. since 2 is connected to 4, and 4 is connected to 11, 11 is connected to 12, 12 is connected to 7 and so on. I am not sure how to program this in a simple way.
Another example to make it clear
1 2
2 3
3 6
6 1
to be changed to
1 2 3 6 1
Hope the question is clear.
3 件のコメント
Image Analyst
2015 年 7 月 26 日
編集済み: Image Analyst
2015 年 7 月 26 日
OK, it looks like you're considering only numbers on the same row, then when a row is "used" you look for the number in a different row. What if the next number shows up in 5 rows? Which of the 5 rows do you pick next? What if there is a row that is not connected to anything prior? For example, what if row two had 991 and 999 in it? You'd never get to that row. There could be many such rows that are "unattached".
採用された回答
Azzi Abdelmalek
2015 年 7 月 26 日
編集済み: Azzi Abdelmalek
2015 年 7 月 26 日
a= [2 4
4 11
5 7
5 10
7 12
8 10
11 12
2 8];
test=0;
out=a(1,: );
d=a(2:end,:);
while test==0
[ii,jj]=find(d==out(end),1);
if ~isempty(ii)
out(end+1)=d(ii,setdiff(1:2,jj));
d(ii,:)=[];
else
test=1;
end
end
out
2 件のコメント
Azzi Abdelmalek
2015 年 7 月 26 日
It's possible to pre-allocate the variable out to size(a,1), then take what we have to take. I tried it, but it doesn't improve the speed.
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