フィルターのクリア

Silly question Incorrect Calculation

2 ビュー (過去 30 日間)
Jay
Jay 2015 年 7 月 25 日
コメント済み: Rena Berman 2017 年 1 月 12 日
I have a nested if statement that states if the condition is not met run another script and then compare again until it meets the condition or meets the maximum iterations.
unk_row = 6
for it_cnt = 1:20
% for all elements in del_hat_cal (6 coords)
for unk_cnt = 1:unk_row
if (abs(del_hat_cal(unk_cnt,1))) < sqrt(C_x_hat(unk_cnt,unk_cnt))
del_hat_cal = del_hat_cal
% else if any of the values dont meet the requirements => run the iteration
% subroutine.
else IterationSubscript_1_2
end
disp ('Iterations')
disp(it_cnt)
end
The code executes correctly until the second iteration of it_cnt
It then says that the if statement is met and del_hat_cal = del_hat_cal.
I.e. that
0.00102504692433755
0.000892842647618351
0.00348097622168141
0.00306579321936951
0.00315561723971564
0.000665510381349233
< sqrt [
1.20641569956672e-05
9.90305275269894e-06
3.62427182962373e-05
2.53803334328813e-05
4.60943640122694e-05
1.44380191794682e-05 ]
Does anyone know why in the second iteration for it_cnt MatLab shows the condition is met, thus del_hat_cal = del_hat_cal ?
  1 件のコメント
Rena Berman
Rena Berman 2017 年 1 月 12 日
(Answers Dev) Restored question.

サインインしてコメントする。

採用された回答

Walter Roberson
Walter Roberson 2015 年 7 月 25 日
but 0.00102504692433755 is less than sqrt(1.20641569956672e-05) which is approximately 0.003 . The condition is met.
My guess, based upon the comment in the code, is that you want
unk_row = 6
for it_cnt = 1:20
% for all elements in del_hat_cal (6 coords)
unk_cnt = 1:unk_row
if all((abs(del_hat_cal(unk_cnt,1))) < sqrt(C_x_hat(unk_cnt,unk_cnt)))
del_hat_cal = del_hat_cal
% else if any of the values dont meet the requirements => run the iteration
% subroutine.
else IterationSubscript_1_2
end
disp ('Iterations')
disp(it_cnt)
end

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeGraphics Object Programming についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by