Hlep change the program .As easy and automatic.

i=1;
while (100-2^i>0)
i=i+1;
end
k=i-1
e1=100-2^k
while (e1-2^k<0)
k=k-1;
end
k1=k
e2=e1-2^k1
while(e2-2^k1<0)
k1=k1-1;
end
k2=k1
e3=e2-2^k2

1 件のコメント

the cyclist
the cyclist 2015 年 7 月 16 日
Please explain the problem with the code. Are you getting an error? Are you getting an unexpected result? Does this code run too slowly for your purpose?
You need to help explain all this to us, if you want us to help you.

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2015 年 7 月 16 日

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2021 年 8 月 20 日

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