フィルターのクリア

Is it possible to evaluate a variant control expression that contains a value inside a structure array?

2 ビュー (過去 30 日間)
To specify conditions for variant choices of a variant subsystem, I normally use a Simulink.Variant object such as
Simulink.Variant('Dev1SubsystemC_Option==2')
and then define Dev1SubsystemC_Option=1 or =2 or =3 in the workspace.
But because my current model is big and complicated, I need to put all parameters including variant settings within an organized structure. So instead of evaluating Dev1SubsystemC_Option in the base workspace, I tried to use
Simulink.Variant('Device(1).Subsystem_C.Option==2')
Error due to multiple causes.
Caused by:
'Device(1)' is not allowed as the left-hand side of 'Device(1).Subsystem_C' in variant condition expression
'Device(1).Subsystem_C.Option==2'. Only enumerated type names are allowed.
'Device(1).Subsystem_C' is not allowed as the left-hand side of 'Device(1).Subsystem_C.Option' in variant condition
expression 'Device(1).Subsystem_C.Option==2'. Only enumerated type names are allowed.
which gives me errors. I'm not sure why MATLAB doesn't want to accept this Boolean expression. Is there a way to work around this? I'm using MATLAB 2015a.
Thanks
  2 件のコメント
JWiesemann
JWiesemann 2016 年 8 月 3 日
Still no answer after more tha a year? Maybe "MATLAB Answers" is a misleading name.
Josh Chambers
Josh Chambers 2017 年 2 月 10 日
編集済み: Josh Chambers 2017 年 2 月 10 日
This is a pretty weird and serious limitation that I just ran into. Also, what the heck does it mean "Only enumerated type names are allowed"?? Also, please respond mathworks!
2016a here

サインインしてコメントする。

回答 (0 件)

カテゴリ

Help Center および File ExchangeVariant Hierarchical Components についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by