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Break statements still result in the first condition breaking array element being shown - how can it be stopped from being generated?

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Thom
Thom 2011 年 12 月 3 日
Just a little annoying that matlab throws up the value that breaks a condition in the case below - can the code below be changed to solve this please?
For example
A = [ 2 3 4 5 6 9 9 10] %(elements of A matches t)
for t = 1:8;
B(t) = 3*A(t);
if B(t) >= 24;
break
elseif B(t) <= 3;
break
end
end
end
I would like to get from this B = [6 9 12 15 18]- the last three exceed 24.
Instead I get B = [6 9 12 15 18 27]
How can the code be changed so that B(6) = 27 will not be printed?
Many Thanks!

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採用された回答

Fangjun Jiang
Fangjun Jiang 2011 年 12 月 3 日
One solution:
A = [ 2 3 4 5 6 9 9 10] %(elements of A matches t)
for t = 1:8;
B(t) = 3*A(t);
if B(t) >= 24 || B(t)<=3
B(t)=[];
break
end
end

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その他の回答 (1 件)

Naz
Naz 2011 年 12 月 3 日
As far as I understand, you don't care weather you reach the end of the A array or not. As soon as you hit the fist value that is out of (3 24) bound you want to break. Is that right? If so, then you can do the following:
A = [ 2 3 4 5 6 9 9 10] %(elements of A matches t)
for t = 1:length(A)
if 3*A(t) >= 24 || 3*A(t) <=3
break;
else
B(t) = 3*A(t);
end
end

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