logical operation on a varable x

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Arunachalam  D
Arunachalam D 2015 年 7 月 3 日
コメント済み: Star Strider 2015 年 7 月 3 日
For j=1:20
Here if j=1 or j=20 should not proceed further so how to write a code in for loop
End
  1 件のコメント
Azzi Abdelmalek
Azzi Abdelmalek 2015 年 7 月 3 日
What do you mean?

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回答 (3 件)

Star Strider
Star Strider 2015 年 7 月 3 日
Taking a wild guess:
for k1 = 1:20
if (k1 == 1) | (k1 == 20)
continue
end
% Do Something
end
If k1 is 1 or 20, the loop continues to the next iteration without doing anything after the if block. Otherwise, it continues to do whatever is in the loop.
  2 件のコメント
Guillaume
Guillaume 2015 年 7 月 3 日
This, of course, could be simply written as
for k2 = 2:19
%do something
end
So, I'm not sure why the OP is asking the question.
Star Strider
Star Strider 2015 年 7 月 3 日
My guess is that at 1 and 20 it does only one set of operations, and in between, other operations as well. We don’t know the details.

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Hugo
Hugo 2015 年 7 月 3 日
Is this what you are looking for?
for j = 1:20
if j==1 || j==20, continue; end
your_code_goes_here
end
This executes everything after the if except when j is 1 or 20.

Joep
Joep 2015 年 7 月 3 日
You mean something like this because your question is not clear
while stoploop=0
stoploop=j==1|j==20
end
A test you can see it is only true on 1 and 20
for j=1:20
stoploop(j)=j==1|j==20
end

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