Solving Matrices with Symbolic Variables
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I am trying to figure out how to solve a problem such as [A]{X}={0} where [A] is a numerical matrix such as
[1 2 3 4]
[5 6 7 8]
[9 0 1 2]
and {X} is a symbolic matrix with a single numeric value such as
[1x1 sym; 1x1 sym; 1x1 sym; 1]
that is:
[a]
[b]
[c]
[1]
Is there a way to find a,b,c such that [A]{X}={0}
2 件のコメント
Walter Roberson
2020 年 6 月 2 日
null() by itself does not work for the case where one or more of the X vectors are known constants, as is required by the Question.
採用された回答
Andrei Bobrov
2011 年 11 月 30 日
A =[ 1 2 3 4
5 6 7 8
9 0 1 2]
syms a b c
x = [a;b;c]
k = A(:,1:3)\-A(:,end);
for i1 = 1 : numel(x)
eval([char(x(i1)),'=k(i1)']);
end
3 件のコメント
その他の回答 (2 件)
Kaixiang Wang
2016 年 11 月 30 日
編集済み: Kaixiang Wang
2016 年 11 月 30 日
Simply use MATLAB symbolic toolbox and the solve() function.
syms a b c
A=[1 2 3 4;5 6 7 8;9 0 1 2]
X=[a;b;c;1]
sol=solve(A*X)
2 件のコメント
Walter Roberson
2020 年 6 月 2 日
null() by itself does not work for the case where one or more of the X vectors are known constants, as is required by the Question.
Walter Roberson
2011 年 11 月 30 日
編集済み: John Kelly
2014 年 5 月 27 日
3 件のコメント
Walter Roberson
2023 年 11 月 13 日
In particular these days, that page leads to https://www.mathworks.com/help/symbolic/linear-algebra.html
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