Finding the path between two points
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Hi all,
I have two x y z coordinates and I need the path between these two points. It does not necessarily need to be the shortest distance path. I am working with a (3x30) position matrix. The first row represents x, the second row is y and the third row is z.
Point 1: (x1,y1,z1)
Point 30: (x30,y30,z30)
Position matrix: [x1 .......... x30
y1 .......... y30
z1 .......... z30]
Point 1 and point 30 are given. I need something simple that will give me the remaining 28 points within the matrix.
Thanks in advance!
2 件のコメント
James Tursa
2015 年 7 月 2 日
編集済み: James Tursa
2015 年 7 月 2 日
Any restrictions on the path? E.g., is a diagonal jump (two indexes changing at the same time) OK? Can indexes only change a max of 1 for each point?
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James Tursa
2015 年 7 月 2 日
編集済み: James Tursa
2015 年 7 月 2 日
E.g., a somewhat "linear" path allowing "diagonal" jumps (more than one index can change at a time):
Point1 = whatever;
Point30 = whatever;
Pmatrix = [round(linspace(Point1(1),Point30(1),30));
round(linspace(Point1(2),Point30(2),30));
round(linspace(Point1(3),Point30(3),30))];
If the points do not need to be integers, then skip the rounding.
7 件のコメント
James Tursa
2015 年 7 月 2 日
編集済み: James Tursa
2015 年 7 月 2 日
They are not zero ... they are just displaying as zero because of the display format you are using (probably short) and the wide range of values in the result. Try this:
format long g
Then display the result again.
Or just look at the last row by itself:
Pmatrix(3,:)
その他の回答 (1 件)
Image Analyst
2015 年 7 月 2 日
See Steve's 5 part blog series on it: http://blogs.mathworks.com/steve/2011/11/01/exploring-shortest-paths-part-1/
0 件のコメント
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