How datetime and integer or float value can co-habitate in an array?
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I am trying to save both a float or integer value together with a datetime value in an array. Anyway of making both these values cohabitate in an array?
d= 5.5
e = 05-Feb-2015 18:15:59
f= [d e]
Of course this is an error. But I am trying to map integers values to a datetime value. How i can do this. Should i change the datetime to a string?
2 件のコメント
Jan
2015 年 6 月 26 日
The datetime "e" is a string already. So you have actually:
e = '05-Feb-2015 18:15:59'
with the quotes.
Walter Roberson
2015 年 6 月 26 日
Keep in mind that datetime is a newer object class, and members of that class print out without quotes.
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その他の回答 (1 件)
Azzi Abdelmalek
2015 年 6 月 26 日
編集済み: Azzi Abdelmalek
2015 年 6 月 26 日
Use cell array
d= 5.5
e = '05-Feb-2015 18:15:59'
f= {d e}
or
d= 5.5
e =datenum( '05-Feb-2015 18:15:59')
f=[d e]
or use struct array
d= 5.5
e ='05-Feb-2015 18:15:59'
f.date=d
f.value=e
9 件のコメント
yashvin
2015 年 6 月 26 日
Azzi Abdelmalek
2015 年 6 月 26 日
編集済み: Azzi Abdelmalek
2015 年 6 月 26 日
Have you read my answer? you can't write e=05-Feb-2015 18:15:59, it's
e ='05-Feb-2015 18:15:59'
Also, I said you can use cell arrays
array={'05-Feb-2015 18:14:23' '05-Feb-2015 18:14:27' '05-Feb-2015 18:14:31'}
d=5.5
e=array(1)
f={d e}
Azzi Abdelmalek
2015 年 6 月 26 日
If you want to display it
f{1}
f{2}
Walter Roberson
2015 年 6 月 26 日
Azzi probably meant
e = array{1}
rather than
e = array(1)
before the
f = {d e}
yashvin
2015 年 6 月 26 日
Walter Roberson
2015 年 6 月 26 日
t = datetime('now','TimeZone','local','Format','d-MMM-y HH:mm:ss Z');
{t 3; t 5}
Jan
2015 年 6 月 26 日
I do not understand this sentence:
My second query is that my inital datetime array is very long
(about 3000 in length)..how do i convert it automatically between commas?
yashvin
2015 年 6 月 29 日
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