How to get the index of a row from a range of values in an excel file?
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I have a table in excel with 6 column values, namely A,B,C,D,E,F
Given that I specify A=50, C=59500, E=0.786
How do i find the rows in the table that contain these corresponding numbers?
See attached file Thanks
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Guillaume
2015 年 6 月 12 日
編集済み: Guillaume
2015 年 6 月 12 日
You could use ismember if you want exact comparison (i.e your 0.786 is to be found exactly in the spreadsheet down to the last decimal value).
New in R2015a is ismembertol that allows to specify a tolerance which works better for floating point number (bearing in mind that for computers 0.1 + 0.1 + 0.1 is not equal to 0.3, when using double or single precision numbers).
m = xlsread('somefile.xlsx');
A = 50; C = 59500; E = 0.786;
rows = find(ismember(m(:, [1 3 5]), [A C E], 'rows')); %find exact values
%or
rows = find(ismembertol(m(:, [1 3 5]), [A C E], 1e-4, 'ByRows', true)); %find values within tolerance
edit: a few typos
4 件のコメント
Guillaume
2015 年 6 月 12 日
links to doc were provided for you to work out the syntax yourself.
Anyway, fixed the typos. It should work now.
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