Can we find the fourier transform of a function?

1 回表示 (過去 30 日間)
Seetha Rama Raju Sanapala
Seetha Rama Raju Sanapala 2015 年 6 月 8 日
In symbolic tool box, there is a function called fourier which is supposed to give the FT of a function. Example below works
syms x y
f = exp(-x^2);
fourier(f, x, y)
But I find that this does not work. why?
syms x y
f = exp(-x^4);
fourier(f, x, y)
How do you represent a rectangular pulse function in MATLAB so that I can get the FT of it?
rect(t) = 1 if t is between -0.5 and 0.5 inclusive and zero outside.
  2 件のコメント
Walter Roberson
Walter Roberson 2015 年 6 月 8 日
What happens when it "does not work" ?
Seetha Rama Raju Sanapala
Seetha Rama Raju Sanapala 2015 年 6 月 8 日
It just gives the answer as FT of the given function. Basically it just repeats your question as answer. I tried expand, simplify etc but to no avail.

サインインしてコメントする。

回答 (1 件)

Walter Roberson
Walter Roberson 2015 年 6 月 8 日
Rectangular pulse that is 1 between A and B is
Heaviside(x-A) - Heaviside(x-B)

カテゴリ

Help Center および File ExchangeAssumptions についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by