matrix columns and rows manipulating with loop

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sermet
sermet 2015 年 6 月 5 日
回答済み: Guillaume 2015 年 6 月 5 日
n=6; %which is variable, the number of vector's dimension.
i=1:(n-3);
u=cos(i-3);
u=u(:);
jn=(2*cos(u(i)));
% I need to create below arrays with loop w.r.t. the "n" and "jn";
column_1=[0;0;0;jn(1);0;0]; %number of columns is equal (n-3)
column_2=[0;0;0;0;jn(2);0];
column_3=[0;0;0;0;0;jn(3)];

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Guillaume
Guillaume 2015 年 6 月 5 日
No need for loop. You're also better off keeping your 3 columns as one matrix rather than making individually numbered variables.
m = [zeros(n-3, 3); diag(jn)]

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