To accept two numbers from the user; Display all prime numbers between these two numbers.
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To accept two numbers from the user; Display all prime numbers between these two numbers.
To accept two numbers from the user and display perfect numbers between these two numbers.
To accept two numbers from the user and display Armstrong number between these numbers.
Simple coding using DoWhile, IfElse
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採用された回答
B.k Sumedha
2015 年 5 月 28 日
編集済み: Andrei Bobrov
2015 年 5 月 28 日
clc
num1 =input('Enter num1 value ');
num2 =input('Enter num2 value ');
n = num1 : num2;
p = isprime(n);
n(p) %displays the primes
その他の回答 (2 件)
B.k Sumedha
2015 年 5 月 28 日
Try this for Armstrong number:
clear, clc
% Let i take two numbers say 100 to 999
for i = 100 : 999
% We examine every digit in i
is = num2str(i);
% i1 is the left-most digit in i
i1 = str2num(is(1));
% i2 is the middle digit
i2 = str2num(is(2));
% i3 is the right-most digit in i
i3 = str2num(is(3));
% We calculate the probable AN
an = i1^3 + i2^3 + i3^3;
% We compare to the number itself
if i == an
% We display the pair of equal numbers
disp([i an])
end
end
0 件のコメント
B.k Sumedha
2015 年 5 月 28 日
This is for perfect numbers where u can change the values of m and n where they are the two input numbers
n=100;
m=10;
output = zeros(1,n);
for i = m:n
test = 1:i-1;
if (sum(test(mod(i,test) == 0)) == i)
output(i) = i;
end
end
output(output == 0) = []
3 件のコメント
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